How can the function f (x) = x2-6x+8 be rewritten to determine its minimum value?

Minimum value of f (x) = - 1.

Step-by-step explanation:

We convert it to vertex form:

x^2 - 6x + 8

= (x - 3) ^2 - 9 + 8

= (x - 3) ^2 - 1

The minimum value occurs when (x - 3) ^2 = 0 because a square has a minimum value of zero (it cannot be negative for real values of x).

So the function has a minimum value of - 1.