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28 May, 15:41

Find the equation of the axis of symmetry of the following parabola algebraically.

y=2x^2-4x-14

y=2x

2

-4x-14

+3
Answers (1)
  1. 28 May, 19:40
    0
    x = 1

    Step-by-step explanation:

    y = 2x² - 4x - 14

    y = 2 (x² - 2x) - 14

    y = 2 (x² - 2x + 1) - 14 - 2 (1)

    y = 2 (x - 1) ² - 16

    The vertex of the parabola is at (1, - 16). So the equation of the line of symmetry is x = 1.
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