What are the zeros of y=4x^2+3x-1?

Answer: The zeros are x = 1 / 4 or

x = - 1

Step-by-step explanation:

The given equation is expressed as

y = 4x² + 3x - 1

To determine the zeros of the quadratic equation, we would equate it to zero first. It becomes

4x² + 3x - 1 = 0

We would apply the method of factorization. We would find two numbers such that their sum or difference is 3x and their product is - 4x². The two numbers are 4x and

- x. Therefore,

4x² + 4x - x - 1 = 0

4x (x + 1) - 1 (x + 1) = 0

4x - 1 = 0 or x + 1 = 0

x = 1 / 4 or x = - 1