What are the

factors of the binomial

X² - 100?

(x - 10) (x + 10)

Step-by-step explanation:

x^2 - 100 = (x - 10) (x + 10) <==

what u have here is a difference of squares ... x^2 is a perfect square (x) ^2 and 100 is a perfect square (10) ^2

u see : x^2 - 100 = (x) ^2 - (10) ^2 = (x - 10) (x + 10)

a^2 - b^2 = (a - b) (a + b)

now a difference of squares cannot be done if it was x^2 + 100

Answer: (x + 10) (x - 10)

Step-by-step explanation: In this problem, we have a binomial that's the difference of two squares because x² and 100 are both perfect squares and we are subtracting these two squares.

So we set up our two binomials and in the first position we have x · x. In the second position, we use + 10 and - 10 as our factors of - 100.

So our answer is (x + 10) (x - 10).