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5 February, 10:11

Find two consecutive odd integers such that the sum of their squares is 202.

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Answers (2)
  1. 5 February, 11:20
    0
    9 and 11

    Step-by-step explanation:

    The squareroot of 202 is 14 ... so the numbers are both less than 14.

    9*9 = 81

    11*11 = 121

    121+81 = 202
  2. 5 February, 12:57
    0
    9 and 11

    Step-by-step explanation:

    (9^2) + (11^2) Simplify the exponents

    81 + 121 = 202
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