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21 July, 16:17

In a genetics experiment on peas, one sample of offspring contained 450 green peas and 371 yellow peas. Based on those results, estimate the probability of getting an offspring pea that is green. Is the result reasonably close to the value of three fourths that was expected?

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  1. 21 July, 17:18
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    P (G) = 0.55

    the probability of getting an offspring pea that is green. Is 0.55.

    Is the result reasonably close to the value of three fourths that was expected?

    No

    Expected P (G) = three fourths = 3/4 = 0.75

    Estimated P (G) = 0.55

    Estimated P (G) is not reasonably close to 0.75

    Step-by-step explanation:

    Given;

    Number of green peas offspring

    G = 450

    Number of yellow peas offspring

    Y = 371

    Total number of peas offspring

    T = 450+371 = 821

    the probability of getting an offspring pea that is green is;

    P (G) = Number of green peas offspring/Total number of peas offspring

    P (G) = G/T

    Substituting the values;

    P (G) = 450/821

    P (G) = 0.548112058465

    P (G) = 0.55

    the probability of getting an offspring pea that is green. Is 0.55.

    Is the result reasonably close to the value of three fourths that was expected?

    No

    Expected P (G) = three fourths = 3/4 = 0.75

    Estimated P (G) = 0.55

    Estimated P (G) is not reasonably close to 0.75
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