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27 March, 00:58

Divide the following polynomials

(2x2+x+3) / (x-2)

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Answers (1)
  1. 27 March, 02:02
    0
    Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of

    0

    .

    2

    x

    -

    3

    2

    x

    2

    -

    3

    x

    +

    5

    Divide the highest order term in the dividend

    2

    x

    2

    by the highest order term in divisor

    2

    x

    .

    x

    2

    x

    -

    3

    2

    x

    2

    -

    3

    x

    +

    5

    Multiply the new quotient term by the divisor.

    x

    2

    x

    -

    3

    2

    x

    2

    -

    3

    x

    +

    5

    +

    2

    x

    2

    -

    3

    x

    The expression needs to be subtracted from the dividend, so change all the signs in

    2

    x

    2

    -

    3

    x

    x

    2

    x

    -

    3

    2

    x

    2

    -

    3

    x

    +

    5

    -

    2

    x

    2

    +

    3

    x

    After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

    x

    2

    x

    -

    3

    2

    x

    2

    -

    3

    x

    +

    5

    -

    2

    x

    2

    +

    3

    x

    0

    Pull the next term from the original dividend down into the current dividend.

    x

    2

    x

    -

    3

    2

    x

    2

    -

    3

    x

    +

    5

    -

    2

    x

    2

    +

    3

    x

    0

    +

    5

    The final answer is the quotient plus the remainder over the divisor.

    x

    +

    5

    2

    x

    -

    3
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