The mass of two sacks of potatoes is 168 grams. One-eight of the mass of Sack A and three-quarter of the mass of Sack B is 76 grams. Write an equation to find the mass of Sack A.

1/8 (A) + (3/4) (168-A) = 76 is an equation to find the mass of A, the mass of A is 80 grams.

Step-by-step explanation:

What do we know?

Both sacks together are 168 grams. Therefore;

A+B=168

One eighth of sack A and three quarters of sack B is equal to 76 grams. Therefore;

1/8 (A) + (3/4) B=76

Let's solve using the substitution method to find A. First, we need to isolate and then substitute B for an expression containing A.

A+B=168

B=168-A

Now that we have isolated B, we can substitute '160-A' for B in the other equation.

1/8 (A) + (3/4) (168-A) = 76

1/8 (A) - 3/4 (A) + 126=76

1/8 (A) - 3/4 (A) + 126=-50

-5/8 (A) = -50

A=80