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2 November, 14:34

X²+y²=25 xy=12 find the value of (3x+3y) ²

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  1. 2 November, 15:03
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    Step-by-step explanation:

    (a + b) ²=a²+2ab+b²

    (3x+3y) ² = (3x) ²+2*3x*3y + (3y) ²

    =9x² + 18xy + 9y²

    =9x² + 9y² + 18xy

    = 9 * (x²+y²) + 18xy

    =9*25 + 18*12

    =225 + 216

    =441
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