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2 December, 14:53

A car is on a driveway that is inclined 10 degrees to the horizontal. A force of 490 lb is required to keep the car from rolling down the driveway.

a) Find the weight of the car.

b) Find the force the car exerts on the driveway.

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  1. 2 December, 17:00
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    a) weight of the car = 2816,1 lbs

    b) 2773 lbs

    Step-by-step explanation:

    The equilibrium force is 490 lbs. That force keep the car at rest, then

    ∑ Fy = 0 and ∑Fx = 0

    Forces acting on the car:

    The external force 490 lbs

    weight of the car uknown

    Normal force

    sin∠10° = 0,174

    cos∠10° = 0.985

    ∑Fx = 0 mg*sin10° - 490 = 0 ∑Fy = 0 mg*cos10° - N = 0

    mg*0,174 = 490

    mg = 490 / 0,174

    mg = 2816,1 lbs

    weight of the car = 2816,1 lbs

    The Normal force

    mg*cos10° - N = 0 2816,1 * 0,985 = N

    N = 2773 lbs

    Then equal force in magnitude and in opposite direction will car exets on the driveway
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