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30 April, 00:47

A certain forest covers an area of 3800 km^2. Suppose that each year this area decreases by 7.25%. What will the area be after 5 years

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  1. 30 April, 04:16
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    After the fifth year, the area will be 2,608.28 square km.

    Step-by-step explanation:

    Given,

    The area is = 3,800 square km. (or, km^2)

    Decreasing rate = 7.25% per year.

    After 1st year, the area will be decreased to

    = 3,800 - (3,800 x 7.25%)

    = 3,800 - 275.5

    = 3,524.5 square km.

    After 2nd year,

    3,524.5 - (3,524.5 x 7.25%) = 3,524.5 - 255.52625 = 3,268.97375 sq. km

    After 3rd year,

    3,268.97375 - (3,268.97375 x 7.25%) = 3,268.97375 - 237.00 = 3,031.97375 sq. km.

    After 4th year,

    3,031.97375 - (3,031.97375 x 7.25%) = 3,031.97375 - 219.818 = 2,812.15575 sq. km.

    After 5th year,

    2,812.15575 - (2,812.15575 x 7.25%) = 2,812.15575 - 203.88 = 2,608.27575 sq. km.

    Therefore, after the fifth year, the area will be 2,608.28 square km.

    If we do a complex method,

    The formula will be,

    Total area x (1 - decreasing rate) ^ year

    = 3,800 x (1 - 0.0725) ^5 = 2,608.28 square km.
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