Sian is twice as old as her sister Abigail. They divide 30 pounds in the ratio of their ages. How much do Sian and Abigail receive?

Sian would receive 20 Pounds while Abigail would receive 10 Pounds.

Step-by-step explanation:

Given that Sian is twice as old as her sister Abigail, it means that if Abigail's age is T years then Sian's age would be 2T years.

If they divide 30 pounds in the ratio of their ages, the ratio of their ages will be

T : 2T (Ratio of Abigail's gae to Sian's age)

The amount received by Abigail

= T / (T + 2T) * 30

= T/3T * 30

= 1/3 * 30

= 10 Pounds

The amount received by Sian

= 2T / (T + 2T) * 30

= 2T/3T * 30

= 2/3 * 30

= 20 Pounds