Solve the following equation by making an appropriate substitution. x Superscript negative 2 Baseline minus 2 x Superscript negative 1 Baseline minus 15 equals 0 Make an appropriate substitution and rewrite the equation in quadratic form. Let uequals xz-1 x Superscript negative 1 , then the quadratic equation in u is u^2-2u-15 (-5) (u+3) (u-5) (u+3).
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