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7 October, 16:17

A rectangular parking lot has a length 20 H more

than its width. Its area is 2400H². What are

the dimensions of the lot?

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Answers (1)
  1. 7 October, 18:16
    0
    Let the width = X

    The length would be X + 20

    Area = Length x width:

    2400 = x * (x+20)

    Simplify:

    2400 = x^2 + 20x

    Subtract 2400 from both sides:

    x^2 + 20x - 2400 = 0

    Factor:

    (x-40) (x+60) = 0

    Solve for both x's:

    x = 40 and x = - 60

    The dimensions of a parking lot have to be positive values so you would use x = 40.

    The width = x = 40

    The length = x + 20 = 40+20 = 60

    The dimension of the parking lot is 40H x 60H
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