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4 October, 22:53

If h (x) = 5 + x and f (x) = 5, which expression is equivalent to (kn) (x) ?

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  1. 5 October, 02:43
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    Step-by-step explanation:

    The question is not correctly written, here is the correct question.

    If h (x) = 5 + x and k (x) = 5, which expression is equivalent to (koh) (x) ?

    (koh) (x) can be rewritten as k{h (x) }

    Since h (x) = 5+x then, k{h (x) } = k (5+x)

    Note that k (x) can be written as 5x°

    k (5+x) = 5 (5+x) °

    Since any value raise to the power of zero is 1, then;

    k (5+x) = 5 (1)

    k (5+x) = 5

    (koh) (x) = k{h (x) } = 5

    For (hok) x;

    (hok) x = h{k (x) }

    = h (5)

    = h (5x°)

    Since h (x) = 5+x

    h (5x°) = 5+5x°

    h (5x°) = 5+5 = 10

    (hok) x = h (k (x)) = 10
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