Which is a polar form of the following parametric equations?

x=4sin^2 theta

Y=4 sin theta cos theta

a) r=1/4sin theta cod theta

b) r=2

c) r=16sin^2 theta

d) r=4sin theta

Question

Mathematics

Jude Barber

16 July, 07:04

Which is a polar form of the following parametric equations?

x=4sin^2 theta

Y=4 sin theta cos theta

a) r=1/4sin theta cod theta

b) r=2

c) r=16sin^2 theta

d) r=4sin theta

+2

Answers (1)

Know the Answer?

Mueller · Answer 1

r=4sin (theta)

Step-by-step explanation:

x=4sin^2 (theta) y=4sin (theta) cos (theta

theta=arcsin ((sqrtx) / 2)

y=4sin (arcsin (sqrtx/2)) cos (arcsin (sqrtx/2))

graph each to see they line up

Which is a polar form of the following parametric equations?x=4sin^2 thetaY=4 sin theta cos thetaa) r=1/4sin theta cod thetab) r=2c) r=16sin^2 thetad) r=4sin theta

Which is a polar form of the following parametric equations?

x=4sin^2 theta

Y=4 sin theta cos theta

a) r=1/4sin theta cod theta

b) r=2

c) r=16sin^2 theta

d) r=4sin theta