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30 August, 11:13

Anne, Becky and Charlotte had sums of money in the ratio 7:6:5. One of them gave £9 to one of the others and this changed the ratio (in the same order of names) to 6:5:4. The total sum of money remained the same; what was it?

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  1. 30 August, 12:15
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    The total sum of money is £810

    Step-by-step explanation:

    The parameters given are;

    The ratio of the sum Anne, Becky and Charlotte had = 7:6:5

    One of them gave one of the others £9 and the new ratio becomes 6:5:4

    The total sum of money remains the same = M

    The initial fraction amount of the total sum of money each had is given as follows;

    Anne = 7 / (7 + 6 + 5) * M = 7/18·M = 0.389·M

    Becky = 6/18·m = 1/3·M

    Charlotte = 5/18·M = 0.278·M

    After one of them gave £9 to one of the others, the fraction amount of the total sum of money each had became;

    Anne = 6 / (6 + 5 + 4) * M = 6/15·M = 0.4·M

    Becky = 5/15·m = 1/3·M

    Charlotte = 4/15·M = 0.267·M

    Therefore, given that Anne's fraction of the total sum of money increased while Charlotte's fraction of the total sum of money decreased, it was Charlotte that gave Anne £9

    Therefore, the fraction of the total sum of money equivalent to £9 is found s follows;

    5/18·M - 4/15·M = 1/90·M = £9

    Therefore;

    M = 90 * £9 = £810

    The total sum of money = £810.
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