State the vertical asymptote of the rational function. F (x) = (x-6) (x+6) / x^2-9.

X=6, x=-6

X=3, x=-3

X=-6, x=6

None

x = 3, x = - 3

Step-by-step explanation:

The denominator of f (x) cannot be zero as this would make f (x) undefined. Equating the denominator to zero and solving gives the values that x cannot be and if the numerator is non zero for these values then they are vertical asymptotes.

Solve : x² - 9 = 0 ⇒ x² = 9 ⇒ x = ± 3

The vertical asymptotes are x = - 3 and x = 3