Ask Question
13 July, 19:30

F (x) = 8cos (2x) on (0,2π)

+1
Answers (1)
  1. 13 July, 21:23
    0
    Step-by-step explanation:

    First put the lower limit, i. e., x=0,

    F (x) = 8cos[2 (0) ]=8cos (0) = 8 (1) = 8

    ; cos (0) = 1

    Now, put the upper limit of given interval, i. e., x = π,

    F (x) = 8cos[2 (π) ]=8cos (2π) = 8 (1) = 8

    ; cos (2π) = 1
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “F (x) = 8cos (2x) on (0,2π) ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers