9 times a number has 1 subtracted from it. The result is trebled. The answer is the same if you add 7 to twice the number and multiply the result by 7. What is the number?

The number is 4.

Step-by-step explanation:

Let the number = x.

9 times a number has 1 subtracted from it = 9x-1

The result is trebled=3 (9x-1).

The answer is the same if you add 7 to twice the number and multiply the result by 7 = (7+2x) 7.

Now, 3 (9x-1) = 7 (7+2x)

Opening the brackets, 27x-3=49+14x

Collecting like terms, 27x-14x=49+3

Hence, 13x=50

Dividing both sides by 13, we have x=4.

Therefore, the number is 4.

Answer: 4

Step-by-step explanation: 1) You need to first understand the question and a way to do that is to list plainly the information given.

2) Let the number be (X)

3) For the equation from the first sentence given; 3 (9x-1)

4) From the second sentence; 7 (7+2x)

5) Equating both sentences together, since the question says they are the same 3 (9x-1) = 7 (7+2x)

6) Opening the bracket/expanding the equation ... 27x-3=49+14x

Solving further we will have 13x = 52

X = 52/13

= 4