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9 June, 01:25

Before being put out of service, the supersonic jet Concorde made a trip averaging 120 mi/h less than the speed of sound for 0.1 h and 410 mi/h more than the speed of sound for 3.0 h. If the trip covered 3,990 mi, what is the speed of sound?

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  1. 9 June, 02:10
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    894.19 mi/hr

    Step-by-step explanation:

    Total distance of the trip = 3990 mi

    Let the speed of the sound be 'x' miles per hour

    Now,

    Total distance = Speed * Time

    Therefore,

    According to the question

    3,990 mi = [ (x - 120) * 0.1 ] + [ (x + 410) * 3.0 ]

    or

    3,990 mi = 0.1x - 12 + 3x + 1230

    or

    0.1x + 3x = 2772

    or

    3.1x = 2772

    or

    x = 894.19 mi/hr
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