Given the sequence 12, 6, 3, 3/2, ..., identify the tenth term. Show your work.

U have a geometric sequence. To find the common ratio, divide the second term by the first term. 6/12 = 1/2

an = a1 * r^ (n-1)

n = term to find = 10

a1 = first term = 12

r = common ratio = 1/2

now we sub

a (10) = 12 * 1/2 (10 - 1)

a (10) = 12 * 1/2^9

a (10) = 12 * 1/512

a (10) = 12/512 reduces to 3/128,< = = ur 10th term