5. Solve the quadratic equation.

x

2

-

10

x

+

25

=

0

x2-10x+25=0

A.

x = 5 or

-

5

-5

B.

x = 5

C.

x =

-

5

-5

D.

no real solution

x=5 twice

Step-by-step explanation:

x^2-10x+25=0

multiply the coefficient of x^2 and the last term

1X25=25

find two numbers you can multiply to get 25 and add to get - 10

-5 + (-5) = -10 the middle term

replace - 10x with - 5x - 5x and solve the equation

x^2-5x-5x+25=0

factorise by grouping

x (x-5) - 5 (x-5) = 0

(x-5) (x-5) = 0

Either x-5=0, x=5 or x-5=0, x=5

Therefore x=5 twice.