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19 April, 16:35

Evaluate log base 12 of y^2, given log base 12=16

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  1. 19 April, 18:33
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    y = 12^8

    Step-by-step explanation:

    Log base 12, y^2 = 16

    y2 = 12^16

    y = sqrt (12^16) = (12^16) ^1/2

    y = 12^8
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