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28 January, 10:39

If 5x-4y=22 and 3x+6y=30, what is the value of x-5y

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  1. 28 January, 10:48
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    -4 See Below:

    Step-by-step explanation:

    When you have a system of equations, you need to solve for one variable, and subsitute that variable into the other equation to solve for the other variables value.

    3x + 6y = 30 In this case, it would be easier to solve for x.

    3x = 30-6y Divide both sides by 3

    x = 10-2y

    Now we substitute for x in the other equation.

    5x - 4y = 22

    5 (10-2y) - 4y=22

    50-10y-4y=22

    50-14y=22 Add 14y to both sides

    50 = 14y + 22 Subtract 22 from both sides

    28 = 14y Divide by 14 on both sides.

    y = 2

    Substitute y=2 and solve for x.

    x = 10 - 2y

    x = 10-2*2

    x = 10-4

    x = 6

    Now we know y=2 and x=6, so we can substitute them into x-5y to find its value.

    x - 5y

    = 6-5*2

    =6-10

    = - 4
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