What is an equation of the line that passes through (0, 8) and (4, 0) ?

y = 2 x + 8

y = 2 x + 4

y = - 2 x + 4

y = - 2 x + 8

Question

Mathematics

Jakob Howe

6 August, 12:59

What is an equation of the line that passes through (0, 8) and (4, 0) ?

y = 2 x + 8

y = 2 x + 4

y = - 2 x + 4

y = - 2 x + 8

+5

Answers (1)

Know the Answer?

Elijah Castaneda · Answer 1

Step-by-step explanation:

Say y=ax+b. It goes through (0,8) and (4,0). Therefor we can say 8=a (0) + b which gives us b=8. Then we fill in (4,0) which results in 0=a (4) + 8. Given that, a=-2. so y=-2+8

What is an equation of the line that passes through (0, 8) and (4, 0) ?y = 2 x + 8y = 2 x + 4y = - 2 x + 4y = - 2 x + 8

What is an equation of the line that passes through (0, 8) and (4, 0) ?

y = 2 x + 8

y = 2 x + 4

y = - 2 x + 4

y = - 2 x + 8