2019

Quiz: Chapter 6 Homework

According to recent surveys, 53% of households have personal computers. If a random

sample of 175 households is selected, what is the probability that more than 75, but

fewer than 110 have a personal computer? n-175 53 4

Step-by-step explanation:

n=175, p=0.53

q = 1-q = 1 - 0.53 = 0.47

Since np = (175) (0.53) = 92.75 and nq = (175) (0.47) = 82.25, the normal distribution can be used to

approximate the binomial distribution.

µ = np = (175) (0.53) = 92.75

σ = npq = (175) (0.53) (0.47) = 43.5925 = 6.60246

For binomial distribution, P (X > 75) and P (X < 110)

For normal distribution, P (75 + 0.5 < X < 110 - 0.5)

= P (75.5 < X < 109.5)