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5 December, 20:22

what is the probability that a data value and a normal distribution is between a z score - 1.32 and a z score of 0.94

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  1. 5 December, 22:22
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    0.733

    Step-by-step explanation:

    Using a calculator or table:

    P (-1.32 < Z < 0.94) = P (Z < 0.94) - P (Z < - 1.32)

    P (-1.32 < Z < 0.94) = 0.8264 - 0.0934

    P (-1.32 < Z < 0.94) = 0.733
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