When randomly choosing bills from a cup of bills that contains a $1 bill a $2 bill a $5 bill a $10 bill a $20 bill and a $50 bill what is the probability of choosing a $5 bill and a $20 bill

1/36

Step-by-step explanation:

Given the sample space

S = [$1, $2, $5, $10, $20, $50] = 6

Hence the probability of choosing a

$5 bill is

Pr ($5) = 1/6

Also the probability of choosing a $20 bill is

Pr ($20) = 1/6

Therefore the probability of choosing a $5 bill and a $20 bill

Pr ($5,$20) = 1/6*1/6 = 1/36