3 consecutive integers are such that the when the smallest is multiplied by 3 is 18 more than the largest

Answer: 10, 11, 12

Step-by-step explanation:

Let the integers be : x, x + 1 and x + 2

the smallest multiplied by 3 implies 3x

From the first statement

3x = 18 + (x+2)

3x = 18 + x + 2

3x - x = 18 + 2

2x = 20

x = 10

Therefore : the numbers are : 10, 10 + 1 and 10 + 2

the numbers are : 10, 11, 12

10,11,12

Step-by-step explanation:

3 consecutive integers ... x and x + 1 and x + 2

3x = x + 2 + 18

3x = x + 20

3x - x = 20

2x = 20

x = 20/2

x = 10

x + 1 = 10 + 1 = 11

x + 2 = 10 + 2 = 12

ur numbers are 10, 11, and 12