A rectangle has a perimeter of 50 m and a side length of L.

a. Express the other dimension of the rectangle in terms of L.

25-L

Step-by-step explanation:

Let W represent the other side length. The perimeter (P) of the rectangle is ...

P = 2 (W+L)

Solving for W, we get ...

P/2 = W+L

P/2 - L = W

Filling in the given value for P, we find ...

W = 50/2 - L = 25 - L

The other dimension is (25-L) meters.

Answer: The other dimension can be expressed as

(50 - 2L) / 2

Step-by-step explanation: First and foremost, we would let the other dimension be represented by B. Then, the perimeter of a rectangle is measured as L+L+B+B or better put;

Perimeter = 2L + 2B

Where L is the measurement of the longer side and B is the measurement of the shorter side.

In this case the perimeter of the rectangle measures 50m, and this can now be written as

50 = 2L + 2B

Subtract 2L from both sides of the equation

50 - 2L = 2L - 2L + 2B

50 - 2L = 2B

Divide both sides of the equation by 2

(50 - 2L) / 2 = B