Ask Question
9 May, 20:02

If r and s are positive integers, each greater than 1, and if 11 (s-1) = 13 (r-1), what is the least possible value of (r+s) ?

+2
Answers (1)
  1. 9 May, 22:29
    0
    The least value of (r+s) is (12+14) = 26

    Step-by-step explanation:

    Well, first let us solve equation of 11 (s-1) = 13 (r-1), which results in 11s-11=13r-13. Hence, 11s+2=13r. It is stated that r and s both are integers and greater than 1.

    To make sure that r and s are integers, the least value of s must be equal to 14 (s=14) then the least value of r becomes 12 (r=12).

    Finally, the least value of (r+s) is (12+14) = 26.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “If r and s are positive integers, each greater than 1, and if 11 (s-1) = 13 (r-1), what is the least possible value of (r+s) ? ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers