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28 November, 16:00

A ball is thrown upwards and it's height h m, at time t s, is given by h=7t-4.9t2. How long does the ball spend more than 1.5m above ground?

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  1. 28 November, 17:09
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    Answer: From what you wrote the I think the ball is drop

    At time 0 you are 7 meters above ground

    You basically just need to solve for

    1.5 = 7t-4.9t^2

    by rearrange the equation you get

    4.9t^2-7t+1.5=0

    by using Quadratic Formula

    t=1.166s
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