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4 April, 12:27

It was recently estimated that homes without children outnumber homes with children by about seven to five. If there are 2556 homes in a county, how many of them are homes without children?

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  1. 4 April, 12:49
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    929

    Step-by-step explanation:

    For every 11 children, 7 will have homes and 4 will not.

    The fraction of children without homes is 4/11.

    The number of children without homes is

    4/11 * 2556 = 929

    Check:

    The number of children with homes is 2556 - 929 = 1627

    With/Without = 1627/929 = 7.005/4 ≈ 7/4

    OK.
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