Max bought a 100-page journal and writes 1 page per day. Pat bought a 200-page journal and writes 3 pages per day. The equation below can be solved to find the number of days (d) until they will have the same number of pages left in their journals. - d + 100 = - 3d + 200 In how many days (d) will Max and Pat have the same number of pages left in their journals?

d=50

Step-by-step explanation:

-d+100=-3d+200

Subtract 100 from both sides

-d+100-100=-3d+200-100

Simplify

-d=-3d+100

Add 3d to both sides

-d+3d=-3d+100+3d

Simplify

2d=100

Divide both sides by 2

/frac{2d}{2}=/frac{100}{2}

Simplify

d=50

In 50days

Step-by-step explanation:

Since the equation below can be used to find the number of days (d) until they will have the same number of pages left in their journals - d + 100 = - 3d + 200, this equations will be solved to get 'd'

Given the equation;

-d + 100 = - 3d + 200

Collecting like terms we will have;

-d+3d = 200-100

2d = 100

d = 50

This shows that Max and Pat will have the same number of pages left in their journals in 50days.