The sum of three consecutive numbers is 63, find the numbers

Three consecutive numbers can be

x, (x+1), and (x+2).

x + (x+1) + (x+2) = 63

3x + 3 = 63 (add like terms)

3x = 60 (minus the three)

x = 20, meaning (x+1) = 21, and (x+2) = 22

Answer: 20, 21, and 22

Step-by-step explanation: This problem states that the sum of 3 consecutive numbers is 63 and it asks us to find the numbers.

First represent your numbers as follows.

X ⇒ first number

X + 1 ⇒ second number

X + 2 ⇒ third number

Since their sum is 63, our equation reads x + (x + 1) + (x + 2) = 63.

Simplifying on the left, we get 3x + 3 = 63.

Subtract 3 from both sides and 3x = 60.

Divide both sides by 3 and x = 20.

So our first number, x, is 20.

Our second number, x + 1 would then equal 21.

Our last number, x + 2, would be 22.

So our 3 consecutive numbers are 20, 21, and 22.