Solve each of these systems using the substitution method. Make sure to check your answers!

2x + 3y = - 4

x - 2y = 5

X - 2y = 5

X - 2y + 2y = 5 + 2y

X = 5 + 2y

Plug this into first formula.

2X + 3y = - 4

2 (5 + 2y) + 3y = - 4

10 + 4y + 3y = - 4

10 + 7y = - 4

10 - 10 + 7y = - 4 - 10

7y = - 14

7y/7 = - 14/7

y = - 2

Now plug Y back into 2x + 3y = - 4

2x + 3 (-2) = - 4

2x - 6 = - 4

2x - 6 + 6 = - 4 + 6

2x = 2

2x/2 = 2/2

x = 1

Check by plugging X & y values in either formula.

2 (1) + 3 (-2) = - 4

2 - 6 = - 4

-4 = - 4