How many grams of water would require 4000 joules of heat to raise its temperature from

65°C to 100°C? The specific heat of water is 4.181?

Answer: 27.33 g water

Step-by-step explanation:

For this problem, we will need to use the equation for heat: q=mCΔT. Since we are given heat, change in temperature, and specific heat, all we have to do is plug them in to find grams.

4000J=m (4.181J/g°C) (100-65°C) [find change in temperature]

4000J=m (4.181J/g°C) (35°C) [divide both sides by specific heat and change in temperature]

m=27.33 g