A ball is thrown straight up with a speed of 12 meters per second near the surface of Earth. What is the maximum height reached by the ball?

maximum height = 7.347m

Step-by-step explanation:

maximum height = (U²sin²θ) / 2g

where θ = 90° as the ball is thrown straight up.

sin90°=1, so our formula reduces to;

H = U²/2g

U=12m/s, g=9.8m/s²

H = 12² / (2*9.8)

H=7.347m

Answer:H=7.339m

Step-by-step explanation:

The formula to find maximum height is:

H = v^2 / (2 * g)

V means speed=12 m/s

g means acceleration due gravity (constant) = 9.81m/s^2

Apply the formula

H = (12^2) / (2*9.81)

H=144/19.62

H=7.339m