Ask Question
1 November, 11:30

Two cars leave from the same location but travel opposite directions. The first car travels an average of 50 mi/hr and leaves 15 minutes before the second car, which travels an average of 55 mi/hr. How long will each car travel before they are 200 mi apart?

+4
Answers (1)
  1. 1 November, 13:41
    0
    First car will take 121.2 minutes

    Second car will take 108 minutes

    Step-by-step explanation:

    The first car travels at 50 mi/hr

    After 121.2 minutes, the distance traveled is = (50/60) mi/min * 121.2 = 101 miles

    Second car travel at 55 mi/hr

    After 108 minutes, the distance traveled = (55/60) mi/min * 108 = 99 miles

    Total amount of miles travel by first car and second car after 121.2 minutes and 108 minutes respectively = 200 miles
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Two cars leave from the same location but travel opposite directions. The first car travels an average of 50 mi/hr and leaves 15 minutes ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers