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19 September, 00:19

Find the sum of first 51term of an AP whose second and third term are 14 and 18 respectively

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  1. 19 September, 02:23
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    Step-by-step explanation:

    a₂ = 14

    a₃ = 18

    d = a₃ - a₂ = 18 - 14 = 4

    a₁ = 14 - 4 = 10

    nth term = a + (n-1) d

    a₅₁ = 10 + 50 * 4

    = 10 + 200

    = 210
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