The sum of two numbers is 32. the sum of 3 times the larger and 7 times the smaller is 128

Smaller number = 8 (x)

Larger number = 24 (y)

Step-by-step explanation:

x+y=32

7x+3y=128

Solving by Elimination

-3x-3y = - 96

7x+3y=128

4x=32

4x/4=32/4

x=8

-7x-7y = - 224

7x+3y=128

-4y = - 96

-4y/-4 = - 96/-4

y=24

Check answer

x+y=32

8+24=32

7x+3y=128

7 (8) = 3 (24) = 138

56+72=128

128=128