Given P (A) = 0.072, P (B) = 0.180, and P (C) = 0.027, and that events A, B, and C are mutually exclusive, what is the P (A or B or C) ?

Given P (A) = 0.072, P (B) = 0.180, and P (C) = 0.027, and that events A, B, and C are mutually exclusive, then P (A or B or C) is 0.279

Solution:

Given that probability of event A is P (A) = 0.072

Probability of event B is P (B) = 0.180

Probability of event C is P (C) = 0.027

Also event A, B and C are mutually exclusive.

Need to determine P (A or B or C)

For mutually exclusive events

P (A or B or C) = P (A) + P (B) + P (C)

= 0.072 + 0.180 + 0.027 = 0.279

Hence probability of occurrence of event A or event B or event C, where A, B and C are mutually exclusive events is 0.279.