Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0=2x2+3x-8?

Quadratic formula: x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction

A. 1.39

B. 2.00

C. 2.89

D. 3.50

Step-by-step explanation:

The given quadratic equation is

2x^2+3x-8 = 0

To find the roots of the equation. We will apply the general formula for quadratic equations

x = - b ± √b^2 - 4ac]/2a

from the equation,

a = 2

b = 3

c = - 8

It becomes

x = [ - 3 ± √3^2 - 4 (2 * - 8) ]/2*2

x = - 3 ± √9 - 4 ( - 16) ]/2*2

x = [ - 3 ± √9 + 64]/2*2

x = [ - 3 ± √73]/4

x = [ - 3 ± 8.544]/4

x = (-3 + 8.544) / 4 or x = (-3 - 8.544) / 4

x = 5.544/4 or - 11.544/4

x = 1.386 or x = - 2.886

The positive solution is 1.39 rounded up to the nearest hundredth

its a. 1.39