The tens digit of a two-digit number is 3 less than the units digit. Find the original number, if the sum of that number and the number reversed is 143.

Let ...

x=ones digit

x-3=tens digit

The number in terms of x would be ...

10 (x-3) + x = 11x-30

The number with its digits reversed would be ...

10 (x) + x-3 = 11x-3

And ...

11x-30+11x-3=143 We can solve for x!

22x=176

x=8

The number would be 58.

answer: 58

58

Step-by-step explanation:

8-5=3

58+85=143