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8 May, 22:49

The tens digit of a two-digit number is 3 less than the units digit. Find the original number, if the sum of that number and the number reversed is 143.

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Answers (2)
  1. 9 May, 01:46
    0
    Let ...

    x=ones digit

    x-3=tens digit

    The number in terms of x would be ...

    10 (x-3) + x = 11x-30

    The number with its digits reversed would be ...

    10 (x) + x-3 = 11x-3

    And ...

    11x-30+11x-3=143 We can solve for x!

    22x=176

    x=8

    The number would be 58.

    answer: 58
  2. 9 May, 02:02
    0
    58

    Step-by-step explanation:

    8-5=3

    58+85=143
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