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13 November, 03:34

How to Factor 8m^2+30m+7

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Answers (2)
  1. 13 November, 03:39
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    By using the quadratic formula, and setting a=8, b=30, and c=7, you end up with:

    [-30 + / - SqurRt (30^2-4 (8) (7)) / 2 (8) ]

    After simplifying that equation, you end up with (-30 + / - 26) / (16)

    When solving for the equation where 26 is positive, the result for m is m = - 0.25

    When solving for when 26 is negative, the result is m = - 3.5

    since m^2 has a coefficient of 8, you would multiply m = - 0.25 by 4 to get 4m = - 1. Then you would multiply the other m by 2, to get 2m = - 7

    setting those two equations for m equal to zero would leave you with (4m+1) (2m+7).

    This could have also been done without the quadratic formula if you guessed right on which coefficients for m to use
  2. 13 November, 04:17
    0
    (2m+7) (4m+1)

    I have the way to factor when a not equal 0. you take a*c. So in this equation I get m^2+30m+56. Then factor this equation. (m+28) (m+2). Then take those number divided by a. a = 8 in this case, so (m+7/2) (m+1/4). Can't put the denominator in the parentheses, so put ythe number in the bottom with m. So

    (2m+7) (4m+1).

    I'm not good at explaining. But this is my way to factor the equation with a not equal 0
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