suppose that there are two types of tickets to a show: advance and same-day. the combined cost of one advance ticket and one same-day ticket is $65. for one performance, 25 advance tickets and 40 same-day tickets were sold. the total amount paid for the tickets was $2150. what was the price of each kind of ticket?

Question

Mathematics

Cecelia Bartlett

21 March, 00:20

suppose that there are two types of tickets to a show: advance and same-day. the combined cost of one advance ticket and one same-day ticket is $65. for one performance, 25 advance tickets and 40 same-day tickets were sold. the total amount paid for the tickets was $2150. what was the price of each kind of ticket?

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Answers (1)

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Ariel Marks · Answer 1

The Answer is: Price of Advanced Tickets: $30. Price of Same Day tickets: $35.

Step-by-step explanation:

Amount of Advanced + Amount of Same = $65

a + s = $65

a = 65 - s

25 tickets times the adult price plus 40 tickets at the same day price equals $2,150. Setup the equation, substitute, and solve for s:

25a + 40s = $2150

25 (65-s) + 40s = 2150

1625 - 25s + 40s = 2150

15s = 2150 - 1625

15s = 525

s = 525 / 15 = $35.

a = 65 - 35 = $30.

Proof:

25 (30) + 40 (35) =

$750 + $1,400 = $2,150