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17 July, 09:15

Solve the system of equations.

y = 2x

y = x2 - 15

+4
Answers (1)
  1. 17 July, 12:45
    0
    two solutions : (-3; -6), (5; 10)

    Step-by-step explanation:

    hello:

    the system is : y = 2x ... (*)

    y = x2 - 15 ... (**)

    put the value of y use (*) in (**):

    2x = x² - 15

    x²-2x-15 = 0

    (x+3) (x-5) = 0

    x+3 = 0 or x-5=0

    x = - 3 or x = 5

    case 1 : x = - 3 y = 2 (-3) = - 6

    case 2 : x=5 y = 2 (5) = 10

    two solutions : (-3; -6), (5; 10)
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