Solve the quadratic equation 3x² + 2x-4=0

Give your answers to 2 decimal places.

3x² + 2x - 4 = 0

Δ = b² - 4. a. c

Δ = 2² - 4. 3. - 4

Δ = 4 - 4. 3. - 4

Δ = 52

x = (-b + - √Δ) / 2a

x' = (-2 + √52) / 2.3

x'' = (-2 - √52) / 2.3

x' = 0,8685170918213297

x'' = - 1,5351837584879966

2 Decimal places

x' = 0,87

x'' = - 1,54

Answer:.8685