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25 September, 12:38

Simplify (3a^n) ^3 times (1/3a^n) ^3

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  1. 25 September, 13:35
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    Step-by-step explanation:

    From the given indices

    (3a^n) ^3 X (1/3a^n) ^3

    We can rewrite the equation to be

    (3a^n) ^3 X (3a^-n) ^3

    We father simplify;

    3a^3n X 3a^-3n

    Since we have same base, we add their relative powers, we solve thus,

    3a^ (3n-3n)

    = 3a^0

    = 3 X a^0 = 3 X 1

    =1
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